pptx, 2.29 MB
pptx, 2.29 MB
docx, 223.37 KB
docx, 223.37 KB
docx, 256.73 KB
docx, 256.73 KB

This lesson describes the formation of dipeptides & polypeptides and the different levels of protein structure with reference to specific examples in living organisms. Both the engaging PowerPoint and accompanying resources have been designed to cover specification points 2.1.2 (l) & (m) of the OCR A-level Biology A course and make continual links to previous lessons such as amino acids as well as to upcoming lessons like antibodies.

The start of the lesson focuses on the formation of a peptide bond during a condensation reaction so that students can understand how a dipeptide is formed and therefore how a polypeptide forms when multiple reactions occur.
The main part of the lesson describes the different levels of protein structure. A step by step guide is used to demonstrate how the sequences of bases in a gene acts as a template to form a sequence of codons on a mRNA strand and how this is translated into a particular sequence of amino acids known as the primary structure. The students are then challenged to apply their understanding of this process by using three more gene sequences to work out three primary structures and recognise how different genes lead to different sequences. Moving forwards, students will learn how the order of amino acids in the primary structure determines the shape of the protein molecule, through its secondary, tertiary and quaternary structure and time is taken to consider the details of each of these. There is a particular focus on the different bonds that hold the 3D shape firmly in place and a quick quiz round then introduces the importance of this shape as exemplified by enzymes, antibodies and hormones. Students will see the differences between globular and fibrous protein and again biological examples are used to increase relevance. The lesson concludes with one final quiz round called STRUC by NUMBERS where the students have to use their understanding of the protein structures to calculate a numerical answer.

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