I had a combination padlock on my toolbox with Easter eggs inside and the students were tasked to calculate the code to open it using the information given.
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Excellent fun! I get the following: <br /> <br /> a = 12.6<br /> b = 22,114,665<br /> c = 12.92<br /> d = 120,960<br /> e = 3030<br /> f = 264.6<br /> g = -480<br /> h = 486<br /> i = 5<br /> j = 20<br /> k = 112.5<br /> l = 395.75<br /> <br /> Final answer is -20.0872180523 so the code is 201, presumably. But this might be wrong...<br /> Anyway, we realy enjoyed this, many thanks.
Looks great! Thanks!
Love this! Really challenging & my y12 Further Maths group enjoyed it too. Here are our answers...<br /> <br /> a=12.6 b=22114665 c=12.92 d=120960 e=3030 f=264.6 g=-480 h=486 j=20 k=121.5 l=395.75<br /> <br /> So lock combination is -18.546.. so to 3 sig figs -18.5 . Therefore digits are 185? We all got this answer eventually but we could have made mistakes! Hope this helps. <br />
This looks really great - thank you! Ummm.... don't suppose you have the answers? I'll have to work it out myself!
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