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Math Tricks - Quickly numbers that end in 5
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Math Tricks - Quickly numbers that end in 5

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The 5’s times table refers to the multiplication table for the number 5. It shows the results of multiplying 5 by the numbers from 1 to 10. The speed math is the ability to perform rapid mental calculations, such as addition, subtraction, multiplication, and division. This can be achieved by utilizing mental shortcuts, breaking down numbers into more manageable parts, and employing techniques like approximation and estimation. However, Vedic mathematics does provide various techniques and shortcuts for performing mathematical calculations efficiently. Some of the commonly known techniques include: The term “Ekadhikena Purvena” used to quickly square numbers that end in 5. Example: 35^2 When using “Ekadhikena Purvena”, you take a number ending in 5 and follow these steps to find its square: Take the non-5 part of the number and multiply it by itself plus 1. 1.1> Append 25 to the result obtained in step 1. 1.2> To illustrate with an example, let’s consider the number 35: The non-5 part is 3, so we multiply 3 by itself plus 1: 3 × (3 + 1) = 3 × 4 = 12. 2.1> Append 25 to the result: 1225. 2.2> Therefore, 35^2 is equal to 1225. This technique simplifies the process of squaring numbers ending in 5, allowing for quicker mental calculations.
Easy Math - Addition Facts Practice for Kids
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Easy Math - Addition Facts Practice for Kids

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What is Addition in Maths? Addition is the process of adding two or more items together. Addition in Maths is the method of calculating the sum of two or more numbers. It is a primary arithmetic operation that is used commonly in our day-to-day life. One of the most common uses of addition is when we work with money, calculate our grocery bills, or calculate time. In this article, let us learn more about the addition definition, the addition symbol, addition sums, the parts of addition, addition with regrouping, and number line addition, along with some addition examples in wordsheet.
Mental Math - Multiply from 11, 111, 1111 in 5 seconds + Flashcard
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Mental Math - Multiply from 11, 111, 1111 in 5 seconds + Flashcard

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To multiply a number by 11, 111, 1111, and so on using Vedic Math, follow these steps: The most significant digit of the answer is the leftmost digit of the original number, and the least significant digit is the rightmost digit. The middle digits are formed by adding the digits of the original number in groups starting from right to left and then left to right. Keep adding up to the depth of the number of 1s in the multiplier. For example: To multiply 23 by 111: The answer is 2553. To multiply 87 by 111: The answer is 9657. To multiply 2312 by 1111: The answer is 2568632. You can apply this method to various examples (flashcard) like: 52 x 11 552 x 11 5525 x 11 45 x 111 212 x 111 32 x 1111 Vedic Math simplifies multiplication by numbers like 11, 111, and more, making calculations quicker and easier.
Math Tricks - How to Estimate Square Roots for Fast Calculations
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Math Tricks - How to Estimate Square Roots for Fast Calculations

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Estimate : Get as close as possible to the number you’re trying to square root by finding two perfect square roots that gives a close number for final exam in math or physics. Estimating square roots using the binomial theorem is a technique that can provide a more accurate approximation compared to the basic mental math method. The binomial theorem allows us to expand expressions of the form (a + b)^n, and when applied to square roots, it can help us estimate them more precisely. Here’s how you can do it: Let’s say you want to estimate the square root of a number “x.” 1. Choose a convenient perfect square: Identify a perfect square that is close to the number "x." Let's call this perfect square "a^2." 2. Write the square root as a binomial expression: Express the square root of "x" as the square root of the perfect square (a^2) plus a small adjustment term "b." √x ≈ √(a^2 + b) 3. Apply the binomial theorem: Now, use the binomial theorem to expand the expression √(a^2 + b) to get a more accurate approximation. √(a^2 + b) ≈ a + (b / (2a)) The higher the value of “n” you choose when applying the binomial theorem, the more accurate your estimate will be. For a rough estimate, using “n = 1” is often sufficient. Let’s illustrate this with an example. We want to estimate the square root of 48 using the binomial theorem, with a convenient perfect square of 49 (7^2). 1. Choose the perfect square: a^2 = 49 (7^2). 2. Write the square root as a binomial expression: √48 ≈ √(49 + (48 - 49)) ≈ √(49 - 1) ≈ √(7^2 - 1) ≈ √(7^2 + (-1)) 3. Apply the binomial theorem with n = 1: √(7^2 + (-1)) ≈ 7 + (-1 / (2 * 7)) ≈ 7 - 0.0714 ≈ 6.9286 So, the estimated square root of 48 using the binomial theorem is approximately 6.9286, which is closer to the actual square root of 48 (around 6.9282). Keep in mind that this method can be more time-consuming than the basic estimation technique, but it provides a more accurate result.
Easy Math - Division for Kids by Box method
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Easy Math - Division for Kids by Box method

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Box Method , Why Does it Matter? Are you an upper elementary teacher who is stressing out over long division? Interested in learning how to do box method division? This easy, step-by-step guide will have you doing long division with minimal stress in no time! The box method division provides a visual representation of the division process, which can be helpful for students in understanding how division works. It’s a useful alternative to traditional long division, especially for those who benefit from a more concrete and visual approach to mathematical concepts.
Fast Addition - Tips and Tricks to Increase Your Speed
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Fast Addition - Tips and Tricks to Increase Your Speed

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Vedic Mathematics is a system of mathematical techniques and principles that originated in ancient India and is found in the sacred texts known as the Vedas. The term "Vedic" refers to the Vedic period in Indian history, which dates back thousands of years. Depending of addition in Vedic Mathematics are classified in the form of Sutras as below. Lets see the Vedic Mathematics addition techniques: Ten Point Circle (General Technique) Break apart the addends (General Technique) Calculation from left to right (Specific Technique) Addition using Dot method (Specific Technique) Column-wise Addition (Specific Technique) These are just a couple of examples of the many addition techniques found in Vedic Mathematics. The system as a whole offers a wide range of methods that can be applied to different scenarios, depending on the numbers being added and the desired level of mental calculation. It's important to note that while Vedic Mathematics techniques can be useful for certain individuals and situations, they are not universally applicable or superior to traditional methods. Some people find these techniques intuitive and helpful, while others may prefer traditional methods or modern approaches. Ultimately, the choice of technique depends on personal preference and the specific problem at hand.
The Butterfly Method for Fractions with adding subtracting, dividing Flashcards
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The Butterfly Method for Fractions with adding subtracting, dividing Flashcards

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The butterfly method, also known as the cross-multiplication method or the Chinese method, is used for multiplying or dividing fractions. The method involves creating a butterfly-like diagram where the numerators and denominators of the fractions are crossed and multiplied diagonally. The butterfly method is a helpful technique for performing multiplication and division of fractions using mental math. Here are some tips for using the butterfly method with mental math: *Simplify the fractions before starting: *If possible, simplify the fractions before using the butterfly method. For example, if you are multiplying 2/3 by 6/8, you can simplify 6/8 to 3/4 before using the butterfly method. Use mental multiplication tricks: There are many mental math tricks for multiplying numbers quickly. For example, you can use the distributive property (a x (b + c) = a x b + a x c) to break down one of the fractions into smaller parts. You can also use multiplication tables or mental multiplication strategies such as doubling and halving. Cross-cancel common factors: If the numerator of one fraction is divisible by the denominator of the other fraction, you can cross-cancel the common factor before multiplying. For example, if you are multiplying 2/3 by 6/8, you can cross-cancel the factor of 2 to get 1/3 x 3/4. Simplify as you go: Simplify the product of each diagonal multiplication as you go along. For example, if you are multiplying 2/3 by 6/8, you can simplify 2/8 to 1/4 as you multiply diagonally. Check your answer: After completing the multiplication or division, check your answer by simplifying it to its lowest terms or verifying that it makes sense in the context of the problem. Here is an example of using the butterfly method for multiplication with mental math: 2/3 x 6/8 **Step 1: **Simplify the fractions (if possible): 2/3 x 3/4 Step 2: Use mental multiplication tricks: 2 x 3 = 6 3 x 4 = 12 Step 3: Cross-cancel common factors: 2/3 x 3/4 = 1/3 x 1/4 **Step 4: **Simplify as you go: 1/3 x 1/4 = 1/12 Step 5: Check your answer: 1/12 is already in its lowest terms, so we’re done. The final answer is 2/3 x 6/8 = 1/12.
Fastest way to find multiply (large numbers) by Vedic mental math
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Fastest way to find multiply (large numbers) by Vedic mental math

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The Nikhilam Method is a Vedic Mathematics technique used for fast and efficient calculations of multiplication and division. It involves using the concept of complements to simplify the calculation process. The Nikhilam method is a technique for solving multiplication problems where one of the numbers is close to a base number, such as 10, 100, 1000, and so on. It involves subtracting the difference between the given number and the base number from both the numbers being multiplied, and then multiplying the differences. Finally, the result is added back to the product of the base and the difference. Let’s say we want to multiply 98 by 102 using the Nikhilam method with a base of 100. Example 98x102 Step 1: Find the difference between the given number and the base number 98 - 100 = -2 102 - 100 = 2 Step 2: Multiply the differences -2 x 2 = -4 Step 3: Add the result from Step 2 to the product of the base and the difference Multiply the base number 100 x 100 = 10000 Step 4: The given numbers to the result from Adding Step 2 and Step 3 = 10000 -4 = 9996 Therefore, 98 x 102 = 9,996. Note that this method may take some practice to get used to, but once you become comfortable with it, you will be able to perform these calculations much faster than with traditional methods.